Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
9514 1404 393
Answer:
x -y = -5
3x +y = -11
Step-by-step explanation:
We assume you want two linear equations. Since you know a point on each line, the only thing you need to choose is the slope of the two lines through that point. We can make the slopes be +1 and -3, for example. Then the point-slope equations are ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
y -1 = +1(x +4)
y -1 = -3(x +4)
We can use these equations "as is", or put them in whatever form you like. I personally prefer "standard form:" ax+by=c.
First equation:
y -1 = x +4 . . . . . . eliminate parentheses
-5 = x -y . . . . . . . keep positive x term, put x and y together, separate from the constant
x - y = -5 . . . . . . standard form
Second equation:
y -1 = -3x -12 . . . . eliminate parentheses
3x +y = -11 . . . . . . add 3x+1 to both sides
__
A system of equations with solution (-4, 1) is ...
- x - y = -5
- 3x + y = -11
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.