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Sagot :
Answer:
a -> 3
b -> 4
c -> 1
d -> 5
e -> 2
Step-by-step explanation:
We apply the properties to solve this question.
a. √4x^2y^4
[tex]\sqrt{4x^2y^4} = \sqrt{4}\sqrt{x^2}\sqrt{y^4} = 2xy^2[/tex]
So a -> 3
b. √8x^2y
[tex]\sqrt{8x^2y} = \sqrt{8}\sqrt{x^2}\sqrt{y} = \sqrt{4*2}x\sqrt{y} = \sqrt{4}\sqrt{2}x\sqrt{y} = 2x\sqrt{2}\sqrt{y} = 2x\sqrt{2y}[/tex]
So b -> 4
c. √4x^2y
[tex]\sqrt{4x^2y} = \sqrt{4}\sqrt{x^2}\sqrt{y} = 2x\sqrt{y}[/tex]
So c -> 1
d. √16xy^2
[tex]\sqrt{16xy^2} = \sqrt{16}\sqrt{x}\sqrt{y^2} = 4\sqrt{x}y = 4y\sqrt{x}[/tex]
So d -> 5
e. √8xy^2
[tex]\sqrt{8xy^2} = \sqrt{8}\sqrt{x}\sqrt{y^2} = \sqrt{4*2}\sqrt{x}y = \sqrt{4}\sqrt{2}\sqrt{x}y = 2y\sqrt{2}\sqrt{x} = 2y\sqrt{2x}[/tex]
So e -> 2
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