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Left parenthesis 5 plus 2 square root of 6 right parenthesis squared = a plus b square root of 6 then the value of a and b are

Sagot :

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]33[/tex] and [tex]\frac{20\sqrt{3}}{3}[/tex], respectively.

Step-by-step explanation:

The statement is equivalent to the following mathematic expression:

[tex]\left(5 + 2\sqrt{2})^{2} = a + b\cdot \sqrt{6}[/tex] (1)

By definition of the perfect square trinomial:

[tex]25 + 20\cdot \sqrt{2} + 8 = a + b\cdot \sqrt{6}[/tex]

[tex]33 + 20\sqrt{2} = a + b\cdot \sqrt{6}[/tex]

And by direct comparison we have the following system:

[tex]a = 33[/tex] (2)

[tex]b\cdot \sqrt{6} = 20\sqrt{2}[/tex] (3)

By (3), we solve for [tex]b[/tex]:

[tex]b = \frac{20}{\sqrt{3}}[/tex]

[tex]b = \frac{20\sqrt{3}}{3}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]33[/tex] and [tex]\frac{20\sqrt{3}}{3}[/tex], respectively.