Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Determine the maximum or minimum value of the quadratic function from its equation.

Determine The Maximum Or Minimum Value Of The Quadratic Function From Its Equation class=

Sagot :

You'll need to multiply the function out to get it in the form y = ax^2 + bx + c, in this case it would be y = 4x^2 + 16x + 20.

We can immediately see that y = 20 would be the y value for the pivot point for the equation, and since the equation is positive it woukd have a concave shape. Thus it woulc be a minimum of 20, since there are no points lower than that on the y-axis.

Plotting functions like this on desmos helps you get a better understanding of how they work. I recommend you try! ;)

Answer:

Below in bold.

Step-by-step explanation:

y = 4(x + 2)^2 + 4

As the coefficient of x^2 is positive it will have a minimum value.

The minimum value is the last term  = 4.