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Determine the voltage which must be applied to a 1 k 2 resistor in order that a current of
10 mA may flow.​


Sagot :

Answer:

The correct solution is "20 volt".

Explanation:

Given that:

Current,

I = 10 mA

or,

 = [tex]10\times 10^{-3} \ A[/tex]

Resistance,

R = 2 K ohm

or,

  = [tex]1\times 10^3 \ ohm[/tex]

Now,

The voltage will be:

⇒ [tex]V=IR[/tex]

By putting the values, we get

        [tex]=10\times 10^{-3}\times 2\times 10^{3}[/tex]

        [tex]= 20 \ volt[/tex]