Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Let the weight of the full Volume of nails in the box be W.
Let the weight of the box be B.
2/3 W + B = 130 ........i From the first statement.
3/8 W + B = 74 ......ii From the second statement.
Equation (i) Minus (ii)
2/3 W - 3/8 W + B - B = 130 - 74
(16W - 9W) / 24 = 56
7W / 24 = 56.
W = 56 * 24 / 7
W = 192 Pounds.
Substituting V = 64 in equation (i)
2/3 W + B = 130
2/3 * 192 + B = 130
2 * 64 + B = 130
128 + B = 130
B = 130 -128 = 2.
Therefore, weight of box, B = 2 pounds.
Let the weight of the box be B.
2/3 W + B = 130 ........i From the first statement.
3/8 W + B = 74 ......ii From the second statement.
Equation (i) Minus (ii)
2/3 W - 3/8 W + B - B = 130 - 74
(16W - 9W) / 24 = 56
7W / 24 = 56.
W = 56 * 24 / 7
W = 192 Pounds.
Substituting V = 64 in equation (i)
2/3 W + B = 130
2/3 * 192 + B = 130
2 * 64 + B = 130
128 + B = 130
B = 130 -128 = 2.
Therefore, weight of box, B = 2 pounds.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.