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Sagot :
[tex]15+3|5x-10|=24\\\\Formula\ for\ absolute\ value\\\\
|a|=a,\ for\ a \geq 0\\ or\\|a|=-a,\ for\ a<0\\\\
15+3(5x-10)=24\ \ \ \ or\ \ \ \ 15+3(-5x+10)=24\\\\
15+15x-30=24\ \ \ \ or\ \ \ \ 15-15x+30=24\\\\
15x-15=24\ \ \ \ \ or\ \ \ \ \ -15x+45=24\\\\
15x=39\ \ \ \ or\ \ \ \ \ -15x=-21\\\\
x=\frac{39}{15}\ \ \ \ or\ \ \ \ x=\frac{21}{15}[/tex]
[tex]15+3|5x-10|=24\\
3|5x-10|=9\\
|5x-10|=3\\
5|x-2|=3\\
|x-2|=\dfrac{3}{5}\\
x-2=\dfrac{3}{5} \vee x-2=-\dfrac{3}{5}\\
x=\dfrac{3}{5}+2 \vee x=-\dfrac{3}{5}+2\\
x=\dfrac{3}{5}+\dfrac{10}{5} \vee x=-\dfrac{3}{5}+\dfrac{10}{5}\\
x=\dfrac{13}{5} \vee x=\dfrac{7}{5}\\[/tex]
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