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Sagot :
slope is rise over run or (y₁-y₂)/(x₁-x₂)
(x,y)
(1,3)
(3,-2)
(3-(-2))/(1-3)=(3+2)/(1-3)=5/-2
slope is -5/2
(x,y)
(1,3)
(3,-2)
(3-(-2))/(1-3)=(3+2)/(1-3)=5/-2
slope is -5/2
(1,3), (3,-2)
m=(y2-y1) / (x2-x1) where (x1 = 1) (y1= 3) (x2=3) (y2=-2)
m=(-2-3)/(3-1)
m=-5/2
therefore slope = -5/2
m=(y2-y1) / (x2-x1) where (x1 = 1) (y1= 3) (x2=3) (y2=-2)
m=(-2-3)/(3-1)
m=-5/2
therefore slope = -5/2
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