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Sagot :
x is the seats in the small van.
y is the seats in the large van = (x + 6). Since the large has 6 more seats.
Since the 2 vans can transport 57 people.
Small van makes 2 trips = 2x.
Large van makes one trip = (x + 6).
2x + (x +6) = 57
2x + x + 6 = 57
3x + 6 = 57
3x = 57 -6
3x = 51
x = 51/3
x = 17.
The larger van has (x + 6) = (17 + 6) = 23.
The larger van has 23 seats.
y is the seats in the large van = (x + 6). Since the large has 6 more seats.
Since the 2 vans can transport 57 people.
Small van makes 2 trips = 2x.
Large van makes one trip = (x + 6).
2x + (x +6) = 57
2x + x + 6 = 57
3x + 6 = 57
3x = 57 -6
3x = 51
x = 51/3
x = 17.
The larger van has (x + 6) = (17 + 6) = 23.
The larger van has 23 seats.
Answer:
The larger van has 23 seats
Step-by-step explanation:
Create a system of Equations:
1. Define variables.
> let x=small van and y=larger van
2. create 2 equations based on the information given.
> y = 6 + x
> 2x + y = 57
3. Use any method to solve
Substitution: 2x + (6 + x) = 57. x=17
now plug x in to the original equation to solve for y (the larger van)
y = 6 + 17 and y = 23
Elimination: 2y = 12 + 2x
y = 57 - 2x
3y = 69 and y = 23
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