Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

c) An aluminum tea kettle with mass 1.10 kg containing 1.80 kg of water is placed on a stove. If no heat is lost to the surroundings, how much heat must be added to raise the temperature from 20o C to 95o C

Sagot :

hamzaahmeds

Answer:

Q = 640425 J = 640.425 KJ

Explanation:

From the law of conservation of energy:

Heat Addition = Heat Gain of Water + Heat Gain of Aluminum Kettle

[tex]Q = m_wC_w\Delta T_w + m_aC_a\Delta T_a[/tex]

where,

Q = Heat addition required = ?

[tex]m_w[/tex] = mass of water =1.8 kg

[tex]m_a[/tex] = mass of aluminum kettle = 1.1 kg

[tex]C_w[/tex] = specific heat capacity of water = = 4200 J/kg.°C

[tex]C_a[/tex]  = specific heat capacity of aluminum kettle = = 890 J/kg.°C

[tex]\Delta T_w[/tex] = [tex]\Delta T_a[/tex] = change in temperature of water and kettle = 95°C - 20°C = 75°C

Therefore,

[tex]Q = (1.8\ kg)(4200\ J/kg.^oC)(75^oC)+(1.1\ kg)(890\ J/kg.^oC)(75^oC)\\[/tex]

Q = 567000 J + 73425 J

Q = 640425 J = 640.425 KJ

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.