Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Suppose of sodium iodide is dissolved in of a aqueous solution of potassium carbonate. Calculate the final molarity of sodium cation in the solution. You can assume the volume of the solution doesn't change when the sodium iodide is dissolved in it. Round your answer to significant digits.

Sagot :

jufsanabriasa

Answer:

0.2762M Na+ in the solution

Explanation:

2.07g of sodium iodide Is Dissolved In 50.ML Of A 0.30M...

To solve this question we need to find the moles of sodium iodide, NaI, that are the same than the moles of sodium cation, Na+. The volume in liters of the solution is 0.050L. The molarity is:

Moles NaI = Moles Na+ -Molar mass NaI: 149.89g/mol-

2.07g NaI * (1mol / 149.89g) = 0.01381 moles NaI = Moles Na+

Molarity:

0.01381 moles Na+ / 0.0500L =

0.2762M Na+ in the solution

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.