At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The Power in a circuit is given by the formula P=I^{2}R, where I is the Current and R is the Resistance. If the Resistance is always constant at 500, the Current is 1, and dI/dt = -0.5, then dP/dt = -500.

True or false and please show work. Thank you

Sagot :

True

Step-by-step explanation:

[tex]P(t) = I^2(t)R[/tex]

Taking the derivative of P(t) with respect to time,

[tex]\dfrac{dP(t)}{dt} = 2I(t)\dfrac{dI(t)}{dt}R[/tex]

[tex]\:\:\:\:\:\:\:\:= 2(1)(-0.5)(500) = -500[/tex]