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What is the factored form of 125a^6-64?

Sagot :

Answer:

(5 a^2 - 4) (25 a^4 + 20 a^2 + 16)

Step-by-step explanation:

Since both terms are perfect cubes, factor using the difference of cubes formula,  

a^3  −  b^ 3 = (a − b) (a^2 + a b + b^2) where a = 5a^2   and  b = 4 .