roshanmalisha4321
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express 26 divide 4 +root3 in form a +b root3 where a and b are integres​

Sagot :

olayemiolakunle65

Answer:

8 - 4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given: [tex]\frac{26}{4 + \sqrt{3} }[/tex]

To express the given question in the form a + b[tex]\sqrt{3}[/tex], we first have to rationalize the denominator of the expression.

Rationalizing the denominator, we have;

[tex]\frac{26}{4 + \sqrt{3} }[/tex] * [tex]\frac{4 - \sqrt{3} }{4 - \sqrt{3} }[/tex]  = [tex]\frac{104 -26\sqrt{3} }{16 -4\sqrt{3} + 4\sqrt{3}- 3 }[/tex]

= [tex]\frac{104 - 26\sqrt{3} }{16 - 3}[/tex]

 = [tex]\frac{26(4 - \sqrt{3} }{13}[/tex]

= 2(4 - [tex]\sqrt{3}[/tex])

= 8 - 4[tex]\sqrt{3}[/tex]

The required form of the given question is therefore 8 - 4[tex]\sqrt{3}[/tex]

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