Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer:
0.319 = 31.9% probability that the wait time will be more than an additional 16 minutes
Step-by-step explanation:
To solve this question, we need to understand the exponential distribution and conditional probability.
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: It has already taken 11 minutes.
Event B: It will take 16 more minutes.
Exponentially distributed with an average wait time of 14 minutes.
This means that [tex]m = 14, \mu = \frac{1}{14}[/tex]
Probability of the waiting time being of at least 11 minutes:
[tex]P(A) = P(X > 11) = e^{-\frac{11}{14}} = 0.4558[/tex]
Probability of the waiting time being of at least 11 minutes, and more than an additional 16 minutes:
More than 11 + 16 = 27 minutes. So
[tex]P(A \cap B) = P(X > 27) = e^{-\frac{27}{14}} = 0.1454[/tex]
What is the probability that the wait time will be more than an additional 16 minutes?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1454}{0.4558} = 0.319[/tex]
0.319 = 31.9% probability that the wait time will be more than an additional 16 minutes
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
