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XYZ ∆ where Angle Y =90° , XZ= 14 m , XY = 6 m . Find YZ ?

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Sagot :

[tex]4 \sqrt{10} [/tex]

Step-by-step explanation:

Use Pythagoras

A^2 + b^2 = c^2

(6)^2 + b^2 = (14)^2

36 + b^2 = 196

B^2 =160

[tex]b = \sqrt{160} [/tex]

[tex]b = 4 \sqrt{10} [/tex]