Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The HEIGHT variable will be used to hold the index numbers of the rows in a multidimensional array. The WIDTH will be used to hold the index numbers of the columns. Which of the following completed for loop could fill that previously declared anArray multidimensional array with the value 0 in each position?(a) for (int n=0; n < HEIGHT; n++) { for (int m=0; m < WIDTH; m++) { int anArray[0][0]; }}(b) for (int n=0; n < HEIGHT; n++) { for (int m=0; m < WIDTH; m++) { } anArray[n][m] = 0; }(c) for (int n=0; n < WIDTH; n++) { for (int m=0; m < HEIGHT; m++) { int anArray[n][m] = { {0,0,0}{0,0,0}{0,0,0}{0,0,0|}{0,0,0}}; }}(d) for (int n=0; n < HEIGHT; n++) { for (int m=0; m < WIDTH; m++) { anArray[n][m] = 0; }}

Sagot :

MrRoyal

Answer:

(d) for (int n=0; n < HEIGHT; n++) { for (int m=0; m < WIDTH; m++) { anArray[n][m] = 0; }}

Explanation:

Given

HEIGHT [tex]\to[/tex] rows

WIDTH [tex]\to[/tex] columns

Required

Fill the array with zeros

Assume the array has already been declared

First, we iterate through the rows; using:

for (int [tex]n=0[/tex]; [tex]n < HEIGHT[/tex]; [tex]n++[/tex]) {

Next, we iterate through the columns

for (int [tex]m=0[/tex]; [tex]m < WIDTH[/tex]; [tex]m++[/tex]) {

Then we fill the array with the iterating variables of rows and the columns

anArray[n][m]

Lastly, close the loops

}}

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.