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[tex]5.5=2\pi \sqrt{\frac{L}{9.8}[/tex]

Sagot :

sqdancefan

9514 1404 393

Answer:

  7.51 m

Step-by-step explanation:

The equation matches that required for finding the length of a pendulum that has a period of 5.5 seconds. We can solve for L to find the length.

  [tex]5.5=2\pi\sqrt{\dfrac{L}{9.8}}\\\\\dfrac{5.5}{2\pi}=\sqrt{\dfrac{L}{9.8}}\\\\\left(\dfrac{5.5}{2\pi}\right)^2=\dfrac{L}{9.8}\\\\L=74.1125/\pi^2\approx7.509[/tex]

The length of a pendulum with period 5.5 seconds is about 7.51 meters.

Numenius

Answer:

The length, L = 7.52 m.

Step-by-step explanation:

The given expression is

[tex]5.5= 2 \pi \sqrt\frac{L}{9.8}\\\\Sqauring on both the sides\\\\5.5 \times 5.5 = 4\pi^2 \times \frac{L}{9.8}\\\\L = 7.52 m[/tex]

The value of length is 7.52 m.

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