Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

[tex]5.5=2\pi \sqrt{\frac{L}{9.8}[/tex]

Sagot :

sqdancefan

9514 1404 393

Answer:

  7.51 m

Step-by-step explanation:

The equation matches that required for finding the length of a pendulum that has a period of 5.5 seconds. We can solve for L to find the length.

  [tex]5.5=2\pi\sqrt{\dfrac{L}{9.8}}\\\\\dfrac{5.5}{2\pi}=\sqrt{\dfrac{L}{9.8}}\\\\\left(\dfrac{5.5}{2\pi}\right)^2=\dfrac{L}{9.8}\\\\L=74.1125/\pi^2\approx7.509[/tex]

The length of a pendulum with period 5.5 seconds is about 7.51 meters.

Numenius

Answer:

The length, L = 7.52 m.

Step-by-step explanation:

The given expression is

[tex]5.5= 2 \pi \sqrt\frac{L}{9.8}\\\\Sqauring on both the sides\\\\5.5 \times 5.5 = 4\pi^2 \times \frac{L}{9.8}\\\\L = 7.52 m[/tex]

The value of length is 7.52 m.

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.