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what Is an equation of the line that passes through points (-12 -8) (-17 -16) ​

Sagot :

First we determine the slope of the equation.
m=y2-y1/x2-x1
=-16-(-8)/-17-(-12)
=-16+8/-17+12
=-8/-5
=8/5

Then we find the y-intercept or b of the equation.
(-12,-8). (-17,-16)
y=mx+b. y=mx+b
-8= 8/5*-12+b. -16=8/5*-17+b
-8= -96/5+b. -16=-136/5+b
b= -96/5+8. b=-136/5+16
b= -56/8. b=-56/5
b=-7

y=8/5x-7. y=8/5x-56/5