Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The radius of a platinum atom is 139 pm. How many platinum atoms would have to be laid side by side to span a distance of 1.39 mm?

Sagot :

Answer:

5x10⁶ atoms of platium have to be laid side by side

Explanation:

1 atom of platium has a radius of 139pm = 139x10⁻¹²m. The distance that occupies 1 atom of platinum is 2 times its ratio:

139x10⁻¹²m*2 = 2.78x10⁻¹⁰m

Assuming there is no distance between to atoms of platinum, just its ratio. The amount of atoms necessary to occupy  1.39mm = 1.39x10⁻³m is:

1.39x10⁻³m / 2.78x10⁻¹⁰m =

5x10⁶ atoms of platium have to be laid side by side