The probability that the first spin lands on blue is [tex]\dfrac{6}{8}[/tex] (6 blue sections of all possible 8)
The probability that the second spin lands on grey is [tex]\dfrac{2}{8}[/tex] (2 gray sections of all possible 8)
So, the probability that the first spin lands on blue and the second spin lands on grey is [tex]\dfrac{6}{8}\cdot\dfrac{2}{8}=\dfrac{3}{4}\cdot\dfrac{1}{4}=\boxed{\dfrac{3}{16}}[/tex]
