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Sagot :

I'm not a master of probabilities, but I reckon the answer is 3/16.
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konrad509
The probability that the first spin lands on blue is [tex]\dfrac{6}{8}[/tex] (6 blue sections of all possible 8)
The probability that the second spin lands on grey is [tex]\dfrac{2}{8}[/tex] (2 gray sections of all possible 8)

So, the probability that the first spin lands on blue and the second spin lands on grey is [tex]\dfrac{6}{8}\cdot\dfrac{2}{8}=\dfrac{3}{4}\cdot\dfrac{1}{4}=\boxed{\dfrac{3}{16}}[/tex]





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