Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
15.87 %
Step-by-step explanation:
z = (.9-1)/.1 = -1
z score of -1 = .1587
The probability that a randomly selected small size package has a weight of less than 0.9 pounds is 15.87 %
We have given that,
A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pounds. If the distribution of weights for the small-size packages of ground meat is approximately normally distributed
What is the formula for the z-score?
[tex]Z = \frac{x - \mu}{\sigma}[/tex]
Z = standard score
x = observed value
[tex]\mu[/tex] = mean of the sample
[tex]\sigma[/tex] = standard deviation of the sample
z = (0.9-1)/0.1 = -1
z of -1 = 0.1587
Therefore the value of the z-score is 0.1587.
To learn more about the Z-score visit:
https://brainly.com/question/25638875
#SPJ2
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
