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Lead is a toxic metal that affects the central nervous system. A Pb-contaminated water sample contains 0.0012 % Pb by mass. What volume of the water in milliliters contains 100 mg of Pb

Sagot :

dsdrajlin

Answer:

8.3 × 10³ mL

Explanation:

Step 1: Calculate the mass of water that contains 100 mg of Pb

The concentration of Pb in the sample is 0.0012% by mass, that is, there are 0.0012 g of Pb every 100 g of water. The mass of water that contains 100 mg (0.100 g) of Pb is:

0.100 g Pb × 100 g Water/0.0012 g Pb = 8.3 × 10³ g Water

Step 2: Calculate the volume corresponding to 8.3 × 10³ g of water

Since the solution is diluted, we will assume the density of the sample is equal than the density of water (1 g/mL).

8.3 × 10³ g × 1 mL/1 g = 8.3 × 10³ mL

The volume of the water in milliliters contains 100 mg of Pb is;

V =  8.3 × 10³ mL

Volume of Solution

We are given the concentration of Pb in the sample as 0.0012% by mass.

That means that there are 0.0012 g of Pb in every 100 g of water.

Thus, the mass of water that contains 100 mg (0.100 g) of Pb is calculated as;

(0.100 g Pb × 100 g of Water)/0.0012 g of Pb = 8.3 × 10³ g of Water

Now, we know that the density of water (1 g/mL) but we are not given the density of the sample.

Thus, since the solution is diluted we can equally say that;

Density of sample = 1 g/mL

Formula for Volume is;

V = mass/density

Thus;

V = 8.3 × 10³ g/1 g/mL

V = 8.3 × 10³ mL

Read more about Volume of solution at; https://brainly.com/question/17055828

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