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The quadratic function f has a vertex at (3,4) and opens upward. The quadratic function g is shown below. Which statement is true? A. The minimum value of g is greater than the minimum value of f. B. The maximum value of g is greater than the maximum value of f. C. The minimum value of f is greater than the minimum value of g. D. The maximum value of f is greater than the maximum value of g.

Sagot :

MrRoyal

Answer:

The minimum value of f(x) is greater than the minimum value of g(x).

Step-by-step explanation:

Given

[tex](h_1,k_1) = (3,4)[/tex] --- vertex of f(x)

[tex]g(x) = 4(x - 4)^2 + 3[/tex] --- g(x) equation

Required

Which of the options is true

First, we identify the vertex of g(x)

A quadratic function is represented as:

[tex]g(x) =a(x - h)^2 + k[/tex]

Where:

[tex](h,k) \to[/tex] vertex

So, we have:

[tex](h_2,k_2) = (4,3)[/tex]

[tex]a = 4[/tex]

If [tex]a>0[/tex], then the curve opens upward

From the question, we understand that f(x) also open upward. This means that both functions have a minimum

The minimum is the y (or k) coordinate

So, we have:

[tex](h_1,k_1) = (3,4)[/tex] --- vertex of f(x)

[tex](h_2,k_2) = (4,3)[/tex] --- vertex of g(x)

The minimum of both are:

[tex]Minimum = 4[/tex] ----  f(x)

[tex]Minimum = 3[/tex] ----  g(x)

By comparison:

[tex]4 > 3[/tex]

Hence, f(x) has a greater minimum

mariamboodiab2005

Answer:

The minimum value of f(x) is greater than the minimum value of g(x).

Step-by-step explanation:

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