Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Suppose 41% of the students in a university are baseball players. If a sample of 524 students is selected, what is the probability that the sample proportion of baseball players will be greater than 44%

Sagot :

Cricetus

Answer:

"0.0808" is the appropriate response.

Step-by-step explanation:

Given:

n = 524

[tex]\hat{P}[/tex] = 41%

or,

   = 0.41

[tex]1-\hat{P}=1-0.41[/tex]

         [tex]=0.59[/tex]

[tex]\mu \hat{P}=\hat{P}[/tex]

     [tex]=0.41[/tex]

Now,

⇒ [tex]6 \hat{P}=\sqrt{\frac{\hat {P}(1-\hat{P})}{n} }[/tex]

         [tex]=\sqrt{\frac{0.41\times 0.59}{524} }[/tex]

         [tex]=0.0215[/tex]

[tex]P(\hat {P}>44 \ percent)[/tex]

or,

[tex]P(\hat{P}>0.44)[/tex]

          [tex]=1-P(\hat{P}<0.44)[/tex]

          [tex]=1-P(\frac{\hat{P}-\mu \hat{P}}{6 \hat{P}} <\frac{0.44-0.41}{0.0215} )[/tex]

          [tex]=1-P(z<1.40)[/tex]

By using the standard normal table, we get

          [tex]=1-0.9192[/tex]

          [tex]=0.0808[/tex]    

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.