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If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive? With four hard disk​ drives, the probability that catastrophe can be avoided is

Sagot :

Answer:

[tex]P(Atleast\ 1) = 0.9999992[/tex]

Step-by-step explanation:

Given

[tex]p = 3\%[/tex] --- rate of hard disk drives failure

[tex]n = 4[/tex] --- number of hard disk drives

See comment for complete question

Required

[tex]P(Atleast\ 1)[/tex]

First, calculate the probability that the none of the 4 selected is working;

[tex]P(none) = p^4[/tex]

[tex]P(none) = (3\%)^4[/tex]

[tex]P(none) = (0.03)^4[/tex]

Using the complement rule, the probability that at least 1 is working is:

[tex]P(Atleast\ 1) = 1 - P(none)[/tex]

This gives:

[tex]P(Atleast\ 1) = 1 - 0.03^4[/tex]

[tex]P(Atleast\ 1) = 0.9999992[/tex]