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Answer:

In this exercise we need to solve the equation

3(x-2) = 2x + 6 - 2

We operate the parentheses and the right side

3(x-2) = 2x + 4

3x - 6 = 2x + 4

We add 6 to both sides

3x -6 + 6 = 2x + 4 + 6

3x = 2x + 10

We substract 2x

3x - 2x = 2x + 10 - 2x

x = 10

sherigroch2

x = 10

Step-by-step explanation:

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