Answered

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The radiation emitted from a star has a maximum intensity at a wavelength of 300 nm. What is the temperature of this star

Sagot :

Answer:

9660 K

Explanation:

From Wien's Displacement Law, we know that;

Peak wavelength = Wien's Displacement constant/temperature

We are given;

Peak wavelength = 300 nm = 300 × 10^(-9) m

Wien's Displacement constant has a value of 2.898 × 10^(-3) K.m

Thus;

Temperature = (2.898 × 10^(-3))/(300 × 10^(-9)) = 9660 K

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