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Some math problems so yep help pls

Some Math Problems So Yep Help Pls class=

Sagot :

Answer:

Step-by-step explanation:

Take this one thing at a time...baby steps to help us keep our sanity. Math does tend to drive a person around the bend...

The first term is the tricky one. If the exponent is negative, it can be rewritten as a positive by putting whatever the exponent is on under a 1. For example:

[tex]x^{-2}=\frac{1}{x^2}[/tex]

So we'll use that to make this simpler.

[tex](-\frac{1}{2})^{-2}=\frac{1}{(-\frac{1}{2})^2 } }[/tex]  Squaring that negative makes it a positive, so we can rewrite as

[tex]\frac{1}{(\frac{1}{2})^2 }[/tex] which simplifies to

[tex]\frac{1}{\frac{1}{4} }[/tex]  What we have there is a fraction over a fraction; namely:

[tex]\frac{\frac{1}{1} }{\frac{1}{4} }[/tex] and the rule for that is to bring the bottom fraction up, flip it and multiply:

[tex]\frac{1}{1}[/tex] × [tex]\frac{4}{1}[/tex] which is 4.

Now for the second part. All we are doing here is squaring that fraction. Remember that squaring a negative makes it a positive, so

[tex](-\frac{1}{2})^2=\frac{1}{4}[/tex] . Now we'll put these together to get the sum

[tex]4+\frac{1}{4}[/tex] and with a common denominator of 4, this becomes

[tex]\frac{16}{4}+\frac{1}{4}[/tex] and that equals

[tex]\frac{17}{4}[/tex], the seond choice down.

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