Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Please help lots of points rewarded

Please Help Lots Of Points Rewarded class=

Sagot :

crossbroil
a of n = 2n^2 - 3
the nth term = 2 times n to the power of 2 minus 3
mhanifa

Answer:

  • tₙ =  2n² - 3

Step-by-step explanation:

Standard form of a quadratic equation:

  • y = ax² + bx + c

Apply same for the quadratic sequence:

  • tₙ = an² + bn + c

Substitute n with 1, 2 and 3 to get the system:

  • -1 = a*1² + b*1 + c  ⇒ a + b + c = -1
  • 5 = a*2² + b*2 + c  ⇒ 4a + 2b + c = 5
  • 5 = a*3² + b*3 + c  ⇒ 9a + 3b + c = 15

Subtract the first equation from the second and subtract the second equation from the third to get:

  • 3a + b = 6
  • 5a + b = 10

Again subtract the equations to find a:

  • 2a = 4
  • a = 2

Then find b and c:

  • b = 3a - 6 = 6 - 6 = 0
  • c = -1 - a - b = -1 - 2 - 0 = -3

Substitute the coefficients back into the equation of the quadratic sequence:

  • tₙ = 2n² + 0n + (-3) = 2n² - 3
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.