Answered

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someone please help me with this problem

Someone Please Help Me With This Problem class=

Sagot :

Answer:

x = [tex]\sqrt{73}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

x² + 7² = ([tex]\sqrt{122}[/tex] )²

x² + 49 = 122 ( subtract 49 from both sides )

x² = 73 ( take the square root of both sides )

x = [tex]\sqrt{73}[/tex]

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