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Calculate the molarity of the H2SO4 solution if 17.45mL of NAOH was necessary to reach the endpoint of the titration. The molarity of the NAOH solution was 0.425 M and 26.30mL of H2SO4 was added to the Erlenmeyer flask.

Sagot :

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Answer:

0.141 M

Explanation:

Step 1: Write the balanced neutralization reaction

H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + 2 H₂O

Step 2: Calculate the reacting moles of NaOH

17.45 mL of 0.425 M NaOH react.

0.01745 L × 0.425 mol/L = 7.42 × 10⁻³ mol

Step 3: Calculate the moles of H₂SO₄ that reacted with 7.42 × 10⁻³ moles of NaOH

The molar ratio of H₂SO₄ to NaOH is 1:2. The reacting moles of H₂SO₄ are 1/2 × 7.42 × 10⁻³ mol = 3.71 × 10⁻³ mol.

Step 4: Calculate the molarity of H₂SO₄

3.71 × 10⁻³ moles of H₂SO₄ are in 26.30 mL of solution.

[H₂SO₄] = 3.71 × 10⁻³ mol/26.30 × 10⁻³ L = 0.141 M

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