shantae4
Answered

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Please help it's for a test.

A car of mass 1000kg is traveling 30m/s

a) What is the kinetic energy?

b) How high will it have to travel up a hill to have the same potential as kinetic energy as this speed? Remember Ep-Ek

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Sagot :

Luv2Teach

Answer:

Explanation:

[tex]KE=\frac{1}{2}mv^2[/tex] so filling in:

[tex]KE=\frac{1}{2}(1000)(30)^2[/tex] so to 2 sig figs (which is actually not accurate, but oh well...)

KE = 450000 J

If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:

450000 = (1000)(9.8)h so

[tex]h=\frac{450000}{(1000)(9.8)}=45.9m[/tex]

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