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Sagot :

reinhard10158

Answer:

the x-intercepts are at

x = -3

x = 0

x = 1

Step-by-step explanation:

ask the points, where the functional value is 0.

2x³ + 4x² - 6x = 0

we see that every term contains an expression of x. so, we can simplify this

x × (2x² + 4x - 6) = 0

so, one solution is plainly visible : x=0

for the other solutions we need to solve the square equation

2x² + 4x - 6 = 0

or even simpler

x² + 2x - 3 = 0

the solution of a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a=1

b=2

c=-3

x = (-2 ± sqrt(2² - 4×1×-3))/(2×1) = (-2 ± sqrt(4 + 12))/2 =

= (-2 ± sqrt(16))/2 = (-2 ± 4)/2 = -1 ± 2

x1 = -1 + 2 = 1

x2 = -1 - 2 = -3

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