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Need help on this!! 10 points!!

Need Help On This 10 Points class=

Sagot :

Answer:

Step-by-step explanation:

The change of base formula is

[tex]log_a(b)=\frac{log_{10}b}{log_{10}a}[/tex] so filling in our given:

[tex]log_{13}}(297)=\frac{log_{10}297}{log_{10}13}[/tex] (Note: you do not have to put the base of 10 in the change of base formula because the "normal" base for a log is 10 and that is how your calculator figures it.)

Do this on your calculator to get

[tex]\frac{log297}{log13}=2.2198[/tex] Not sure how many decimal places you needed!

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