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Which equation in slope-intercept form represents a line that is parallel to y=1/2x-2 and passes through the point (-8,1)?

Sagot :

Answer:

[tex]\displaystyle y=\frac{1}{2}x+5[/tex]

Step-by-step explanation:

We want to find the slope in slope-intercept form of a line that is parallel to:

[tex]\displaystyle y=\frac{1}{2}x-2[/tex]

And passes through the point (-8, 1).

Recall that parallel lines have equivalent slopes.

Since the slope of our given line is 1/2, the slope of our new line must also be 1/2.

We are also given that it passes through the point (-8, 1). Since we are given a slope and a point, we can use the point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

Substitute 1/2 for m and (-8, 1) for (x₁, y₁). Hence:

[tex]\displaystyle y-(1)=\frac{1}{2}(x-(-8))[/tex]

Since we want the equation in slope-intercept form, we can isolate y. Distribute:

[tex]\displaystyle y-1=\frac{1}{2}x+4[/tex]

Therefore, our equation is:

[tex]\displaystyle y=\frac{1}{2}x+5[/tex]