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How many years will it take $2,000 to grow to $3,300 if it is invested at 4.75% compounded​ continuously?

Sagot :

Answer:

10.54263764

Step-by-step explanation:

[tex]3300=2000e^{.0475t}\\\\1.65=e^{.0475t}\\\ln(1.65)=.0475t\\.500775288=.0475t\\t=10.54263764[/tex]

Answer:

It will take about 10.5 years for the investment to reach $3,300.

Step-by-step explanation:

Continuous compound is given by:

[tex]\displaystyle A=Pe^{rt}[/tex]

Where P is the principal, e is Euler's number, r is the rate, and t is the time (in this case in years).

Since our principal is $2,000 at a rate of 4.75% or 0.0475, our equation is:

[tex]\displaystyle A=2000e^{0.0475t}[/tex]

We want to find the number of years it will take for our investment to reach $3,300. So, substitute 3300 for A and solve for t:

[tex]3300=2000e^{0.0475t}[/tex]

Divide both sides by 2000:

[tex]\displaystyle e^{0.0475t}=\frac{33}{20}[/tex]

We can take the natural log of both sides:

[tex]\displaystyle 0.0475t=\ln\left(\frac{33}{20}\right)[/tex]

Therefore:

[tex]\displaystyle t=\frac{1}{0.0475}\ln\left(\frac{33}{20}\right)\approx 10.54\text{ years}[/tex]

It will take about 10.5 years for the investment to reach $3,300.