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Sagot :
Answer:
Hence the answer is given as follows,
Explanation:
Base Case:-
If (num == 0) //This is the base case for the given recursive method
return 1;
If(num % 2!=0) checks whether num is odd.
The above condition is true for all odd numbers and false for even numbers.
if the remainder is not equal to zero when we divide the number with 2 then it is odd.
The method:-
The above recursive method calculates the product of odd numbers up to the given range(that is num)
For num=5 => 15(5*3*1).
For num=7 => 105(7*5*3*1).
For num=10 => 945(9*7*5*3*1).
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