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Sagot :
Answer:
The height of the tree=8.42 m
Step-by-step explanation:
We are given that
Height of Joshua, h=1.45 m
Length of tree's shadow, L=31.65 m
Distance between tree and Joshua=26.2 m
We have to find the height of the tree.
BC=26.2 m
BD=31.65m
CD=BD-BC
CD=31.65-26.2=5.45 m
EC=1.45 m
All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.
[tex]\triangle ABD\sim \triangle ECD[/tex]
[tex]\frac{AB}{EC}=\frac{BD}{CD}[/tex]
Substitute the values
[tex]\frac{AB}{1.45}=\frac{31.65}{5.45}[/tex]
[tex]AB=\frac{31.65\times 1.45}{5.45}[/tex]
[tex]AB=8.42m[/tex]
Hence, the height of the tree=8.42 m
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