Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A dodecahedral die (one with 12 sides numbered from 1 to 12) is tossed once. Find the probability that the number on the upward face is divisible by 3. (Enter the probability as a fraction.)

Sagot :

allaliar

Answer:

the probability is [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

there are 4 numbers on a 12 sided die that can be divided by 3: 3, 6, 9, and 12.

so the probability would be [tex]\frac{4}{12}[/tex], or [tex]\frac{1}{3}[/tex]

fichoh

Using the concept of probability. The chances of having a value which is divisible by 3 is 1/3

Recall :

  • Probability = required outcome / Total possible outcomes

Total possible outcomes = Sample space = 12

Required outcome = numbers divisible by 3 :

  • (3, 6, 9, 2) = 4 outcomes

P(number divisible by 3) = 4 / 12 = 1/3

Therefore, the probability of having a number which is divisible by 3 is 1/3

Learn more : https://brainly.com/question/18405415

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.