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## Sagot :

**Answer:**

The required probability is 0.1.

**Step-by-step explanation:**

red balls = 3

yellow balls = 2

blue balls = 5

Selected balls = 5

Number of elemnets in sample space = 10 C 5 = 1260

Ways to choose 1 red ball and 4 other colours = (3 C 1 ) x (7 C 4) = 105

Ways to choose 5 balls of other colours = 7 C 5 = 21

So, the probability is

[tex]\frac{105}{1260} + \frac {21}{1260}\\\\\frac{126}{1260}=0.1[/tex]