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Consider quadrilateral EFGH.

Quadrilateral E F G H is shown. Sides F G and E H are parallel. Angles E and H are congruent. The length of E F is 4 n minus 4, the length of F G is 3 n + 3, and the length of G H is 2 n + 6.

What is the length of line segment GH?

5 units
7 units
16 units
24 units


Sagot :

Given:

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H,EF=4n-4,FG=3n+3, GH=2n+6[/tex]

To find:

The length of segment GH.

Solution:

Draw a figure according to the given information as shown below.

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H[/tex], it means the quadrilateral EFGH is an isosceles quadrilateral because base angles are equal.

Now, quadrilateral EFGH is an isosceles quadrilateral, so the sides EF and GH are equal.

[tex]EF=GH[/tex]

[tex]4n-4=2n+6[/tex]

[tex]4n-2n=4+6[/tex]

[tex]2n=10[/tex]

Divide both sides by 2.

[tex]n=\dfrac{10}{2}[/tex]

[tex]n=5[/tex]

Now,

[tex]GH=2n+6[/tex]

[tex]GH=2(5)+6[/tex]

[tex]GH=10+6[/tex]

[tex]GH=16[/tex]

Therefore, the correct option is C.

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Answer:

the answer is C

Step-by-step explanation:

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