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The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part to 80 dB during a loud part. Approximately how many times louder is the latter sound

Sagot :

okpalawalter8

Answer:

[tex]\alpha=-3.01dB[/tex]

Explanation:

From the question we are told that:

Sound level intensity

 [tex]\triangle I=40dB-80dB[/tex]

Generally the equation for  intensity level  is mathematically given by

 [tex]\alpha=10log_{10}(I/I_x)dB[/tex]

Where

 I= Intensity measured

 [tex]I_x=Threshold\ of\ audibility[/tex]

 [tex]I_x= 10-12 W / m2[/tex]

 [tex]\alpha= 10 log10 \frac{I_1}{I_x} - 10 log10 \frac{}I_2{I_x}[/tex]

 [tex]\alpha= 10 log10 \frac{I_1}{I_2}[/tex]

 [tex]\alpha=10 log10\frac{40}{80}[/tex]

 [tex]\alpha=-3.01dB[/tex]

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