Answered

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Suppose z varies directly with x and inversely with the square of y. If z = 16 when x = 4 and y = 1 , what is z when x = 8 and y = 9 ?

Sagot :

Answer:

z = 3.6

Step-by-step explanation:

Given that,

z varies directly with x and inversely with the square of y. We can write it as :

[tex]z\propto \dfrac{x}{y}\\\\z=\dfrac{kx}{y}[/tex]

Where

k is constant

Put z = 16 when x = 4 and y = 1

[tex]16=\dfrac{k\times 4}{1}\\\\k=4[/tex]

Now put k = 4, x = 8 and y = 9

[tex]z=\dfrac{4\times 8}{9}\\\\z=3.6[/tex]

So, the value of z is equal to 3.6.

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