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Sagot :
Respuesta:
5.4927 * 10 ^ 4 J
Explicación:
Dado que :
Capacidad calorífica específica del aluminio, C = 0,9 J / g. C °
Temperatura inicial, t1 = 22,8 ° C
Temperatura final, t2 = 94,6 ° C
Masa de aluminio, m = 8.5 * 10 ^ 2 g
Usando la relación:
Q = mcΔt
Δt = t2 - t1 = 94,6 - 22,8 = 71,8 ° C
Q = cantidad de energía térmica requerida
Q = 8.5 * 10 ^ 2 * 0.9 * 71.8
Q = 549,27 * 10 ^ 2 J
Q = 5,4927 * 10 ^ 4 J
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