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10
What are the x- and y-coordinates of point E, which
partitions the directed line segment from A to B into a
ratio of 1:2?
B(-4,9)
9
8
X E
(
mn)(x2 – xı) + x
7-
6
5
4
mm. )(x2 - y) + y
3
-7 -6 -5 4 -3 -2 -14
2 3 4 5 6 7
0 (0, 1)
0 (-1,3)
O(-2,5)
(1,0)
X
-2.
3
A(2,-3)
19


Sagot :

Answer:

Step-by-step explanation:

The formulas to find the x and y coordinates of E are:

[tex]x=\frac{bx_1+ax_2}{a+b}[/tex]  and  [tex]y=\frac{by_1+ay_2}{a+b}[/tex]  where x1, x2, y1, and y2 are from the coordinates of A and B, and a = 1 (from the ratio) and b = 2 (from the ratio). Filling in to find x first:

[tex]x=\frac{2(2)+1(-4)}{1+2}=\frac{4-4}{3}=0[/tex]  and now for y:

[tex]y=\frac{2(-3)+1(9)}{1+2}=\frac{-6+9}{3}=\frac{3}{3}=1[/tex]

The coordinates of E are (0, 1).

Given:

The points are A(2,-3) and B(-4,9).

The point E divides the segment AB in 1:2.

To find:

The coordinates of point E.

Solution:

Section formula: If a point divides a line segment in m:n, then the coordinates of the point is:

[tex]Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)[/tex]

Using the section formula, the coordinates of point E are:

[tex]E=\left(\dfrac{1(-4)+2(2)}{1+2},\dfrac{1(9)+2(-3)}{1+2}\right)[/tex]

[tex]E=\left(\dfrac{-4+4)}{3},\dfrac{9-6}{3}\right)[/tex]

[tex]E=\left(\dfrac{0)}{3},\dfrac{3}{3}\right)[/tex]

[tex]E=\left(0,1\right)[/tex]

Therefore, the coordinates of the point E are (0,1).

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