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Sagot :
Answer:
x=3 y=5
Step-by-step explanation:
it's simultaneous equations so you first try matching the x or the y on both equations
on the first equation the ys are matching so:
4x+y=17
2x+y=11
2x=6
x=3
now that you have x you substitute it back into the equation to get y
6+y=11
-6 -6
y=5
Answer:
(3,5)
(3,2)
(7,0)
(8,1)
Step-by-step explanation:
1.)
Subtract the two equations
(4x+y)-(2x+y)=17-11
2x=6
x=3
plug this into the first equation
4(3)+y=17
y=5
2.) we need one set of the same variable's coefficents to match (so that when we add/subtract the two equations a variable cancels out). To do this multiply the first equation by 1.5
1.5(3x+2y)=13*1.5
4.5x+3y=19.5
Subtract the second equation
(4.5x+3y)-(2x+3y)=19.5-12
2.5x=7.5
x=3
plug this into the first equation
3(3)+2y=13
2y=4
y=2
3.)
Mulitply the first equation by 3
3(x-2y)=7*3
3x-6y=21
subtract this and the second equation
(3x-6y)-(3x+y)=21-21
-7y=0
y=0
plug this into the first equation
x-2(0)=7
x=7
3.)
add the two equations
(x+5y)+(x-5y)=13+3
2x=16
x=8
plug this into the first equation
8+5y=13
5y=5
y=1
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