Answer:
a) 9
b)
[tex]1 \frac{1}{3} [/tex]
c) 15
Step-by-step explanation:
The first step is to cancel out the fraction's denominator if possible.
a)
[tex]15 \times \frac{3}{5} [/tex]
We can cancel the 5 out since 15 divided by 5 is 3. The answer that comes out is
[tex]3 \times \frac{3}{1} [/tex]
Since 3/1 is 3, we can now simplify the values:
[tex]3 \times 3 = 9[/tex]
b)
[tex]4 \times \frac{1}{3} [/tex]
4 is indivisible by three and gives a non-whole value. This is not what we need here.
Instead we should do the division rule and find the remainder.
In this case, 4 divided by 3 gives 1 with a remainder of 1.
[tex]4 \times \frac{1}{3} = \frac{4}{3} [/tex]
After we simplify the non-mixed fraction, we have to change it into a mixed fraction, which consists of a whole number and a fraction. We can split it into the following:
[tex] \frac{4}{3} = 1r1[/tex]
The r1 is just the remainder of the fraction. Since we cannot remove 1 from the remainder, we add it back into the fraction's denominator of 3. This gives:
[tex] \frac{4}{3} = 1 + \frac{1}{3} = 1 \frac{1}{3} [/tex]
c)
[tex] \frac{5}{2} \times 6[/tex]
For this part, we can cancel out 2 since 6 is divisible by 2. This gives:
[tex] \frac{5}{1} \times 3[/tex]
Since 5/1 is 5,
we can now solve part c:
[tex]5 \times 3 = 15[/tex]
