Answered

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Find the points of intersection of the graphs involving the following pair of functions.

f(x)=2x^2 + 3x - 3 and g(x) = -x^2

Sagot :

Numenius

Answer:

The point of intersection is [tex]( \frac{-1\pm\sqrt{5}}{2}, 0)[/tex]

Step-by-step explanation:

f(x) = 2x^2 + 3x - 3 and g(x) = - x^2

By equating them

2x^2 + 3x - 3 = -x^2

3x^2 + 3 x - 3 =  0

x^2 + x - 1 = 0

[tex]x^2 +x - 1 = 0 \\\\x = \frac{-1\pm\sqrt{5}}{2}[/tex]

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