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Express the trigonometric ratios sinA in term of cosA​

Sagot :

Answer:

sinA = ± [tex]\sqrt{1-cos^2A}[/tex]

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract cos²A from both sides )

sin²A = 1 - cos²A ( take the square root of both sides )

sinA = ± [tex]\sqrt{1-cos^2A}[/tex]

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